Find a line perpendicular to y=5/12+3 that passes through the point (3,-12)
1 answer:
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Answer:
B
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 2x + 3y = 4 into this form
Subtract 2x from both sides
3y = - 2x + 4 ( divide all terms by 3 )
y = - x +
← in slope- intercept form
with slope m = -
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
, hence
y = x + c ← is the partial equation of the perpendicular line
To find c substitute (- 2, 15) into the partial equation
15 = - 3 + c ⇒ c = 15 + 3 = 18
y = x + 18 → B
so, is just that product, recall to use "<span>3.1416 as the value of π".</span>
Answer:
Step-by-step explanation:
Before adding we require the fractions to have a common denominator
The lowest common denominator of 2, 5 and 3 is 30, thus
+
+
= +
+
Add the numerators leaving the denominator
= =