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Vladimir79 [104]
3 years ago
7

Sin y = cos ( y + 2° )

Mathematics
1 answer:
Archy [21]3 years ago
8 0

Answer:y=44°

Step-by-step explanation:

Sin y =cos [90°-y]

It is Given that sin y =cos (y+2°)

Cos[90°-y]=Cos(y+2°)

90°-y=y+2°

88°=2y

y=44°

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Solve for t: <br> -4(t+4)=-8t-24
kotykmax [81]

Answer:

\rm{-2

Step-by-step explanation:

Hi there!

\rm{-4(t+4)=-8t-24}

\rm{-4t-16=-8t-24

\rm{-4t+8t=-24+16

\rm{4t=-8

\rm{-2

Thus, -2 is our final answer.

Hope it helps! Enjoy your day!

\bold{GazingAtTheStars}

4 0
2 years ago
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A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

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width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
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sweet [91]

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4 is your answer

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