Answer:
For the answer to the question above, it is -18% because to find rate we subtract the rate, in this case, is .82 or 82% - 1 or 100% and that would give you the rate, in this case, its decreasing by an 18%
-Hope this helps<3
Answer:
4.4
×
10
^−
6
Step-by-step explanation:
Brainliest please :)?
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
brainly.com/question/4318844
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Answer:
√10z^3(z - 1)(z + 1).
Step-by-step explanation:
The GCF is √10z* z^2
= √10z^3
So factoring we get
√10z^3(z^2 - 1) The expression in brackets is difference of 2 squares so:
= √10z^3(z - 1)(z + 1)
Answer:
-2x-1
Step-by-step explanation:
(3x-4)-(5x-3)
Distribute the minus sign
3x-4-5x+3
Combine like terms
3x-5x -4+3
-2x-1