3 years ago

Log8(216)+[log(42)_log(6)]÷log(49)

Mathematics

1 answer:

makkiz [27]3 years ago

7 0

Answer:

3 log (3) + 1/2

Step-by-step explanation:

log8(216) + [log(42) - log(6)] ÷ log(49) =
log (216)/ log (8) + [log (7) + log (6) - log (6)] ÷ 2 log (7) =
3 log (3) log (2) / 3 log (2) + log (7) / 2 log (7) =
3 log (3) + 1/2

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Log8(216)+[log(42)_log(6)]÷log(49)​

Log8(216)+[log(42)_log(6)]÷log(49)