How do division properties help you evaluate expressions?
2 answers:
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We have that
<span>y=-1/3(x+2)</span>²<span>+5
using a graph tool
see the attached figure
we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0) and (1.873,0)
5) the y intercept value is (0,3.667)
</span><span>
</span>
<span>y=-1/3(x+2)</span>²<span>+5
using a graph tool
see the attached figure
we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0) and (1.873,0)
5) the y intercept value is (0,3.667)
</span><span>
</span>
The given equation is :
1. The relationship such that dependent variable (y) is isolated is :
2. The table accompanying this equation :
- x = -4 and y = 0.5
- x = -1 and y = 2
- x = - 0.5 and y = 4
- x = 0 and y = undefined
- x = 0.5 and y = -4
- x = 1 and y = -2
- x = 4 and y = -0.5
3. graph of the given equation is in attachment ~
