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Maru [420]
3 years ago
6

Cna i get some help with dis plz

Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

Let b_1,b_2,\ldots,b_{20} be the 20 marks of the boys, and g_1,g_2,\ldots,g_{10} be the 10 marks of the girls.

We know that the global mean was 70, meaning that

\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70

Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is

b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100

By the same logic, we work with the marks of the boys alone: we know the average:

\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62

And we deduce the sum of the marks for the boys:

b_1+b_2+\ldots+b_{20}=1240

Which implies that the sum of the marks of the girls is 2100-1240=860

And finally, the mean for the girls alone is

\dfrac{860}{10}=86

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