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Roman55 [17]
3 years ago
12

Plzz help please.......​

Mathematics
2 answers:
kap26 [50]3 years ago
6 0

Answer:

6.71

You use pythagoras so you do:

6² + 3² = 45

square root 45 =6.71

ivanzaharov [21]3 years ago
3 0
AB^2= (3-6)^2+(5+1)^2
AB=root 45
AB= 6.71 cm.
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Answer the question below
Alik [6]

Answer:

The Last dog is about a teenage boy who wants to venture out of the dome an odd place he has never seen before. As he began to explore around he discovers the harmlessness of the unusual place. As he later comes across a dog found next to his dead mother mother'scorpse. deciding take the dog with him.

Step-by-step explanation:

7 0
3 years ago
5. Is the sequence arithmetic? If so, identify the common difference.
HACTEHA [7]
5.
aritmetic is same increase per term
14 to 21 is 7
21 to 42 is 21
7≠21
no


6.
decreases by 4 each time
an=a1+d(n-1)
an=10-4(n-1)
n=12 for 12th term
a12=10-4(12-1)
a12=10-4(11)
a12=10-44
a12=-34

it is -34



7.
missing term is y
22+n=y
y+n=34
22+n+n=34
22+2n=34
minus 22 from both sides
2n=12
divide both sides by 2
n=6
22+n=y
22+6=y
28=y

28 is answer



5. no
6. -34
7. 28
6 0
3 years ago
Read 2 more answers
How many significant figures does the measurement 1.50 have?
Aleks [24]

Answer:

22+54

Step-by-step explanation:

5+3

7 0
3 years ago
Read 2 more answers
The volume of a cylinder is 32.25 cubic inches. If a cone has the same height and radius as the cylinder, what is its volume?
Pani-rosa [81]
Since the volume of a cylinder is hπr^2 and the volume of a cone is (hπr^2)/3, the volume of the cone will just be 1/3 the volume of the cylinder with the same radius and height.  In this case:

V=32.25/3=10.75 in^3
6 0
3 years ago
Find a unit vector in the direction of the vector left bracket Start 3 By 1 Matrix 1st Row 1st Column negative 8 2nd Row 1st Col
MrRissso [65]

Answer:

\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]

Step-by-step explanation:

We are required to find a unit vector in the direction of:

\left[\begin{array}{c}-8\\7\\2\end{array}\right]

Unit Vector, \hat{a}=\dfrac{\overrightarrow{a}}{|\overrightarrow{a}|}

The Modulus of \overrightarrow{a} =\sqrt{(-8)^2+7^2+(-2)^2}=\sqrt{117}

Therefore, the unit vector of the matrix is given as:

\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]

5 0
4 years ago
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