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lyudmila [28]
4 years ago
6

Mr. Wallace gave a test to his math classes. He created a histogram that showed the frequency of As, Bs, and Cs. He labeled the

x-axis with the student scores, and the y-axis with the number of students. Which is the correct way to label the intervals on the x-axis? A) 70-79, 80-89, 90-99 B) 70-80, 80-90, 90-100 C) 70-79, 80-88, 88-100 D) 70-74, 75-89, 90-94, 95-100
Mathematics
1 answer:
charle [14.2K]4 years ago
8 0

Answer:

idk im sorry haha

Step-by-step explanation:

NWFBLAWBEF LW

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If a fair die is rolled 6 times, what is the probability, to the nearest thousandth, of
earnstyle [38]

Answer: 0.000

Step-by-step explanation:

6 0
2 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
4 years ago
Suppose you have the 26 letters of the alphabet on separate cards in a hat. You pick out a card, write down the letter, put the
tekilochka [14]
The probability is 4/26 since MATH has 4 letters. It might be a trick question though because you're putting the card back in the hat, therefore it might be different. Sorry if this is too confusing I overthink it lol
8 0
3 years ago
What is the answer btw I know how to multiply i just dont want to multiply 30 × 20 =
alisha [4.7K]

Answer:

600

Step-by-step explanation:

30×20( its like multiplying 3×2 and adding two zeros behind the answer) 6 + two zeros = 600

3 0
3 years ago
In △PQR, find the measure of ∡P. <br><br> (A)30.4°<br> (B)59.6°<br> (C)35.9°<br> (D)54.1°
Kobotan [32]

ANSWER

(D)54.1°

EXPLANATION

The measure of angle P can be calculated using the cosine ratio.

We know the adjacent side to angle P to be 33.8 and the hypotenuse of the right triangle is 57.6 units.

\cos(P)  =  \frac{adjacent}{hypotenuse}

\cos(P) =  \frac{33.8}{57.6}

Take cosine inverse,

P=  \cos ^{ - 1} (\frac{33.8}{57.6} )

P=54.07 \degree

To the nearest tenth, the measure of <P is 54.1°

7 0
3 years ago
Read 2 more answers
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