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kicyunya [14]
3 years ago
7

Please someone help me‼️

Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

6 m

Step-by-step explanation:

The volume of a cone is found by \frac{\pi r^2h}{3}, so we can plug the values in to get 6pi * r^2 / 3 = 72pi, or 6pi * r^2 = 216 pi, so r^2 = 36 and the radius is 6 m.

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What is an equivalent expression (m ^1/3)^ 1/5<br><br> *the fractions are powers btw*
andrezito [222]

\bf ~\hspace{7em}\textit{rational exponents}&#10;\\\\&#10;a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n}&#10;~\hspace{10em}&#10;a^{-\frac{ n}{ m}} \implies&#10;\cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\left( m^{\frac{1}{3}} \right)^{\frac{1}{5}}\implies m^{\frac{1}{3}\cdot \frac{1}{5}}\implies m^{\frac{1}{15}}\implies \sqrt[15]{m^1}\implies \sqrt[15]{m}

5 0
4 years ago
5. f(-2) = 15, f(1) = 9
KengaRu [80]

Answer:

f(x) = -2x + 11

Step-by-step explanation:

okay so if f(-2) = 15 and f(1) = 9

i used desmos to picture it and i got f(x) = -2x + 11

because f(-2) = -2(-2) + 11 = 4 + 11 = 15 so f(-2) = 15

and f(1) = -2(1) + 11 = -2 + 11 = 9 so f(1) = 9

5 0
3 years ago
Which are equivalent expressions?
ollegr [7]

Answer:

  • Check Below.

Step-by-step explanation:

x - y = (6 - 5)(y - x) → False

(x - y) (6 - 5) = 1 → False

x- y = (1)(x - y) → True

x - y = 1 + (x - y) → No solution, False

x - y = (6 - 5)(x - y)  → True

6 0
2 years ago
What is the circumference?
Tanya [424]

Answer: the circumference is the perimeter of a circle or ellipse. That is, the circumference would be the arc length of the circle, as if it were opened up and straightened out to a line segment. More generally, the perimeter is the curve length around any closed figure.

8 0
3 years ago
Read 2 more answers
True or false (Picture provided)
Naya [18.7K]
<h2>Hello!</h2>

The answer is: True.

<h2>Why?</h2>

A counterexample is a way that we can prove that something is not true about a mathematical equation or expression, it's also considered as an exception to a rule.

So:

sec^{2}x-1=\frac{cosx}{cscx}\\\\tg^{2}x=\frac{cosx}{\frac{1}{sinx}}\\\\\frac{1-cos2x}{1+cos2x}=cosxsinx

Then, evaluating we have:

\frac{1-cos(2*45)}{1+cos(2*45)}=cos(45)*sin(45)\\\\\frac{1-0}{1+0}=\frac{\sqrt{2} }{2}*\frac{\sqrt{2}}{2}\\\\1=\frac{(\sqrt{2})^{2} }{4}\\\\1=\frac{2}{4}\\\\1=\frac{1}{2}

Hence, we can see that the equation is not fulfilled, so, 45° is a counterexample for sec^{2}x-1=\frac{cosx}{cscx} and the answer is true.

Have a nice day!

3 0
4 years ago
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