Question

I need help ASAP please (solving rational equations)

Answer 1

$1 - \dfrac{y-1}{y} = \dfrac{1}{y^2 + 2y}$

$\dfrac y y - \dfrac{y-1}{y} = \dfrac{1}{y^2 + 2y}$

$\dfrac{1}{y} = \dfrac{1}{y^2 + 2y}$

$y = y^2 + 2y$

$y^2 + y = 0$

$y(y+1)=0$

$y = 0 \textrm{ or } y = -1$

We rule out y=0 because of the denominator y in the original equation.

Answer: B: y=-1