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expeople1 [14]
3 years ago
7

Which is the equation of the line with slope 5 that contains point (−2, −3)?

Mathematics
2 answers:
Nataly [62]3 years ago
5 0

Answer:

Option C. y+3=5(x+2)

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

In this problem we have

m=5

(x1,y1)=(-2,-3)

substitute the given values

y+3=5(x+2)

Elan Coil [88]3 years ago
3 0

The answer is y = 5x + 7

here's how you get it:

Start with the base   y = mx + b

then imput the points and the slope:

-3 = 5 ( -2 ) + b

Then solve for b

-3 = 5 ( -2 ) + b

-3 = -10 + b

-b = -7

b = 7

so the equation is:

y = 5x + 7 also  

y + 3 = 5(x + 2)

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Answer:

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

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E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}

\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

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3 years ago
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