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3 years ago

Find the area of the figure.

Mathematics

1 answer:

Arisa [49]3 years ago

4 0

Answer:

can u clarify bc area is 2 but 4 things is perimiter

Step-by-step explanation:

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Uriel's hiking stick is 3 2/3 feet long, and Nat's is 3 3/8 feet long. Whose walking stick is longer and by how much?

trasher [3.6K]

Answer:

Uriel's stick is LONGER by 7/24 feet

Step-by-step explanation:

Uriel's hiking stick is 3 2/3 feet long, and Nat's is 3 3/8 feet long. Whose walking stick is longer and by how much?

The above question is solved as

Uriel's stick - Nat's stick

= 3 2/3 feet - 3 3/8 feet

= 7/24 feet

Hence, Uriel's stick is LONGER by 7/24 feet

5 0

3 years ago

lions [1.4K]

Answer:

x/9 = 1/5

x = 9/5

6 0

3 years ago

Which step should be used to prove that point P is equidistant from points R and Q

nydimaria [60]

Step-by-step explanation:

1. If any one side and any one common angle are equal in triangles PQR and PRS, then their corresponding sides are also equal.

2. If two sides and one included angle are equal in triangles PQS and PRS, then their third sides are equal.

3. In triangles PQR and PQS, if one side and one angle are equal, then their corresponding sides and angles are also equal.

4. In triangles PRS and PQS, all three angles are equal.

6 0

3 years ago

A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.

Reptile [31]

Answer:

a.P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}$

Step-by-step explanation:

We are given that a linear differential equation

$y''+2y=e^{3x}+x^3$

We have to find the particular solution

P.I= $\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}$

P.I= $\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}$

P.I= $\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3$

P.I= $\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0}$ (higher order terms can be neglected

P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.Characteristics equation

$D^2+2=0$

$D=\pm\sqrt2 i$

C.F= $C_1cos \sqrt2x+C_2 sin\sqrt2 x$

G.S=C.F+P.I

G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)$

3 0

4 years ago

Factor by grouping<img src="https://tex.z-dn.net/?f=%284y%5E3%20%2B%2028y%5E2%29%20%2B%20%28y%20%2B%207%29" id="TexFormula1" tit

Inessa05 [86]

We have the following expression given:

$(4y^3+28y^2)+(y+7)$

We can start selecting as common factor 4y^2 and we got:

$4y^2(y+7)+(y+7)$

Now we can select y+7 as common factor and we got:

$(y+7)\left\lbrack 4y^2+1\right\rbrack$

So then our final answer would be:

$(y+7)(4y^2+1)$

3 0

1 year ago