Y=11x+4. formula: y=mx+b. insert the number of tickets where x is times 11 then add 4 to your total
Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
Answer:
x = 11
Step-by-step explanation:
3/(3(2x-3)) = 2/(3x+5)
3(2x-3) = 6x - 9
3/(6x-9) = 2/(3x+5)
3(3x+5) = 2(6x-9)
9x + 15 = 12x - 18
12x - 9x = 15 + 18
3x = 33
x = 11
Answer:
0^6= 1000000. The final answer is 25000000.
