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RSB [31]
4 years ago
7

Hey everyone! Please help me figure this out...

Mathematics
2 answers:
shepuryov [24]4 years ago
5 0

Answer:

See below

Step-by-step explanation:

0.82=82/100=82%

22%=22/100=0.22

3/4=0.75=75/100=75%

0.8=0.80=80/100=80%

Hope this helps!

serg [7]4 years ago
4 0

Answer:

column 2: 41/50, 0.82, 82%

column 3: 11/50, 0.22, 22%

column 4: 3/4, 0.75, 75%

column 5: 4/5, 0.80, 80%

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Of the 150 students in 6th grade, 10% earned straight As last quarter. How many students earned straight As?
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Answer: 15 students

Step-by-step explanation:

From the question, we are informed that there are 150 students in 6th grade, and that 10% earned straight As last quarter.

The number of students that earned straight As will be:

= 10% × 150

= 10/100 × 150

= 0.1 × 150

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3 0
3 years ago
What is the value of m in the equation 1/2m-3/4n when n = 8?
kirill [66]

Answer:

-\frac{1}{32}

Step-by-step explanation:

n = 8\\1/2(8) - 3/4(8) = 1/16-3/32

Multiply the numerator and denomiator of 1/16 by 2 so that the denominators are equal and we can subtract.

\frac{1}{16} *\frac{2}{2} =\frac{2}{32}

Then, subtract

\frac{2}{32} -\frac{3}{32} = \frac{2-3}{32} =- \frac{1}{32}

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3 years ago
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Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded
slega [8]

Answer:

4.5 cm=L2

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

H=\sqrt{L1^{2}+L2^{2}  }

Where:

H=6 cm

L1=4 cm

L2=?

We isolate our incognita an we get:

\sqrt{H^{2}-L1^{2}} =L2

We supplant with the given data:

\sqrt{(6cm)^{2}-(4cm)^{2}} =L2

\sqrt{36cm^{2}-16cm^{2}} =L2

\sqrt{36cm^{2}-16cm^{2}} =L2

\sqrt{20cm^{2}} =L2

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3 years ago
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