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USPshnik [31]
3 years ago
15

(02.06)If a piece of ribbon is 6 and 1 over 4. feet long, how long is it in inches?

Mathematics
1 answer:
Alex777 [14]3 years ago
6 0

Answer:

75 inches

Step-by-step explanation:

there are 12 inches in each foot multiply 6 * 12 then multiply .25 or 1/4 by 12 and add them together.

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X^3-2x^2+5x-10=0<br> how do you solve or factor this polynomial?
pshichka [43]

\bf x^3-2x^2+5x-10=0\implies \stackrel{\textit{doing some grouping}}{(x^3-2x^2)+(5x-10)}=0 \\\\\\ \stackrel{\textit{common factoring}}{x^2\underline{(x-2)}+5\underline{(x-2)}}=0\implies \stackrel{\textit{more common factoring}}{\underline{(x-2)}(x^2+5)}=0 \\\\[-0.35em] ~\dotfill\\\\ x-2=0\implies x=2~~~~\textit{\large\checkmark} \\\\[-0.35em] ~\dotfill\\\\ x^2+5=0\implies x^2=-5\implies x=\sqrt{-5}\implies x=i\sqrt{5}\quad \bigotimes

7 0
3 years ago
Please help me on this.
Nonamiya [84]

Answer:

The third option. (the one where it intersects on the y line)

Step-by-step explanation:

If you solve for the system of equations, you will find that it is (0,3), so it intersects on the y line. Additionally, it is on the top because it is positive.

8 0
3 years ago
A water sprinkler sends water out in a circular pattern. How many feet away from the sprinkler can it spread water if the area f
myrzilka [38]

Answer:

The sprinkler can spread water 18 feet away.

Step-by-step explanation:

We are given the following in the question:

Area formed by watering pattern = 1,017.36 square feet

We have to find the how far the sprinkler spread the water.

The sprinkler covers a circular area. We need to find the radius of this circular area to find the how far the sprinkler spread the water.

Area of circle =

A = \pi r^2

where r is the radius of the circle.

Putting values, we get,

1017.36 = 3.14 r^2\\\\r^2 = \dfrac{1017.36}{3.14}\\\\r^2 = 324\\r = \sqrt{324} = 18\text{ feet}

Thus, the sprinkler can spread water 18 feet away.

6 0
4 years ago
Read 2 more answers
Use the graph below to list the x value(s) where the limits as x approaches from the left and right of those integer values(s) a
kirza4 [7]
<span>the limits as x approaches from the left and right of 1 is not equal.</span>
4 0
3 years ago
Please help with 4-9!!!
olya-2409 [2.1K]

sdfsdf

4) \frac{3m+15}{2} = 22.5

Multiply by 2 on both sides

3m + 15 = 45

Subtract both sides by 15

3m = 30

Divide both sides by 3

so m = 3

5) 21= \frac{q+35}{8}

Multiply both sides by 8

168 = q + 35

Subtract both sides by 35

q = 133

6) 14 + \frac{4z}{-11} = 66

Subtract 14 from both sides

\frac{4z}{-11} = 52

multiply by -11 on both sides

4x = 572

Divide both sides by 4

x= 143

7) \frac{3}{5} c - 6 = 9

Add 6 on both sides

\frac{3}{5} c  = 15

Multiply both sides by 5

3c = 75

Divide both sides by 3

c = 25

8) \frac{t}{-2} + 17 = -9

Subtract both sides by 17

\frac{t}{-2} =26

Multiply both sides by -2

t = -52

9) -6 = \frac{5p-(-2)}{-7}

Multiply both sides by -7

42= 5p + 2

subtract 2 from both sides

40 = 5p

Divide both sides by 5

so p = 8






6 0
3 years ago
Read 2 more answers
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