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daser333 [38]
3 years ago
5

The pair of points is on the graph of an inverse variation. Find the missing value.

Mathematics
1 answer:
Ann [662]3 years ago
3 0

Answer:

  x = 16/3

Step-by-step explanation:

y varies inversely with x if ...

  y = k/x

The constant k can be found from ...

  xy = k

For the given point, ...

  2·8 = k = 16

The relation is symmetrical, so we also have ...

  x = k/y = 16/3 . . . . substituting the value at the second given point

The missing value is 16/3.

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PLEASE HELP! CORRECT ANSWERS ONLY!
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Is 7,849 a reasonable number for 49x49
AleksAgata [21]
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Need help badly! Mind helping me out?
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8 0
4 years ago
-5y = -5
Vsevolod [243]

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4 0
4 years ago
State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should
Yuki888 [10]

Solving for <em>Angles</em>

\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
  • One angle and two edges defined, while trying to solve for the <em>second angle</em>
  • ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
3 years ago
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