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You can get this by setting up 2 equations. One for you and one for your friend. Each should have a cost equation. Let x = adult and y = student.
You: 7x + 16y = 120
Friend: 13x + 9 = 140
Solve using any method.
Answer:
y=3x
Step-by-step explanation:
y=kx, where k is constant
3y, 1x...so 3y = 1x
check: looking at the graph at 4.5y, 1.5x where y and x intersect...
4.5=3(1.5)
3 x 1.5 = 4.5
46%d+57%y=55%x42
x+y=42
Find y
x=42-y
46%(42-y)+57%y=23.1
19.31-46%y+57%y=23.1
11%y=23.1-19.31
11%y=3.79
y=34
The answer is D
To solve the problem we could separate the figure into three parts. First figure is a triangle, second figure is a rectangle, third figure is a triangle. See image attached.
Solve each area of the figuresFirst figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²
Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²
Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²
The area of the three figuresarea = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²