Answer:
Bro look it up
Step-by-step explanation:
On google
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1,
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
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If two lines are parallel to one another, then their slopes are identical. The slope in the line above is 3/4. Therefore, a line parallel to that line will also have a slope of 3/4, it will just have a different y-intercept.
Answer:
(3,1)
Step-by-step explanation:
If you plot both of the points on a graph you get another straight line.
When you connect the dots you get 3,1 as the midpoint of the two segments :))
F(x) = 5x
for f(7) you replace x with 7 so it will be : f(7) = 5(7) = 35
