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3 years ago

Find the first, fourth, and eighth terms of the sequence. A(n) = –5 • 2n–1

Mathematics

1 answer:

GenaCL600 [577]3 years ago

8 0

Answer:

-5; -40; -640

Step-by-step explanation:

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Approximate the square root of 278 to the nearest tenth

Dennis_Churaev [7]

Answer:

Answer should be 77280.

Step-by-step explanation:

: ' /

8 0

4 years ago

Will crown the correct answers brainliest 3x

Solnce55 [7]

Answer :

(1) $\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) $\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}$

(3) $\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}$

(4) $\frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}$

(5) $\frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}$

(6) $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}$

Step-by-step explanation :

(1) The given expression is: $\frac{1}{x}+\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) The given expression is: $\frac{1}{5x}+\frac{1}{3y}$

$\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}$

(3) The given expression is: $\frac{1}{7x}-\frac{1}{2y}$

$\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}$

(4) The given expression is: $\frac{2}{5x}+\frac{3}{7y}$

$\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}$

(5) The given expression is: $\frac{7}{11x}-\frac{1}{33y}$

$\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}$

(6) The given expression is: $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}$

$\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}$

7 0

3 years ago

Help pleaaaase it’s urgent

scoundrel [369]

Answer:

volume = 381 in°

Step-by-step explanation:

volume = (16 x 7 x 3) + (0.5 x 3 x 5 x 6) = 336 + 45 = 381 in°

4 0

3 years ago

What is the sum of the first nine terms of this Sequence if the first term is 0?

Harlamova29_29 [7]

Answer:

D. 160

Step-by-step explanation:

The sum of the sequence 1, 2, 3, 4, ... , n is n(n + 1)/2.

Here, you have the sum of 4(1, 2, 3, 4, ... , n), so the sum is 4[n(n + 1)/2]

In this case, the first term is 0, so the last term is the 8th term of the sequence above, so n = 8

4[n(n + 1)/2)] =

= 4[8(9)/2]

= 4[72/2]

= 4(36)

= 144

The closest answer is D. 160

8 0

3 years ago

Read 2 more answers

Please help me with this !!

fomenos

Answer:

akismsksksialoalqoq kskw! sola skkss

Step-by-step explanation:

smksmskkwow!skkw

8 0

3 years ago