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charle [14.2K]
3 years ago
14

You wonder if one's age is independent of whether or not one's willingness to wear masks in public. You ask 100 people whether t

hey are wearing masks in public or not and whether they are under 20 years old, between 20 and 39, between 40 and 59, or 60 or above. Using your data, you calculate a test statistic of 16.5. Using a critical value of 7.82, what is your statistical conclusion?
a) Your results are significant; one's willingness to wear masks is not independent of one's age. b)Your results are significant; one's willingness to wear masks is independent of one's age.
c)Your results are not significant; one's willingness to wear masks is independent of one's age.
d) Your results are not significant; one's willingness to wear masks is not independent of one's age.​
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer:

The statistical conclusion is:

a) Your results are significant; one's willingness to wear masks is not independent of one's age.

Step-by-step explanation:

From this experiment,

The null hypothesis is established as:

H 0 = one's willingness to wear masks is independent of one's age.

The alternate hypothesis is established as:

H 1 = one's willingness to wear masks is not independent of one's age.

In statistics, if the absolute value of the test statistic is greater than the critical value, we declare statistical significance and reject the null hypothesis.

Since the test statistic = 16.5, which is higher than the critical value of 7.82, this establishes statistical significance.  Thus, the null hypothesis is rejected.

Therefore, the statistical conclusion is that one's willingness to wear masks is not independent of one's age.

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Ow many decimals numbers are there whose value equals the average of their digits?
kiruha [24]

Answer:

Step-by-step explanation:

there are infinite numbers between 2 and 3 having average=2.5

2.49,2.51

2.48,2.52

2.47,2.53

2.46,2.54

.................

2.491,2.509

2.492,2.508

2.493,2.507

......................

6 0
2 years ago
Find the discount rate
kifflom [539]

we'd do the same as before on this one as well.

if we take 27.99 to be the 100%, what is 12 off of it in percentage?

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 27.99&100\\ 12&x \end{array}\implies \cfrac{27.99}{12}=\cfrac{100}{x}\implies 27.99x=1200 \\\\\\ x=\cfrac{1200}{27.99}\implies x\approx 42.87

4 0
3 years ago
A triangle has an area of 38.4 cm2. The
lisov135 [29]

Answer:

6cm

Step-by-step explanation:

A = \frac{h_b b}{2}

38.4 = \frac{12.8_b b}{2}

b = 2\frac{A}{h_b}

b = 2\frac{38.4}{12.8} = 6

8 0
3 years ago
Write the complex number in polar form:
emmasim [6.3K]

9514 1404 393

Answer:

  2√30 ∠-120°

Step-by-step explanation:

The modulus is ...

  √((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30

The argument is ...

  arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle

The polar form of the number can be written as ...

  (2√30)∠-120°

_____

<em>Additional comments</em>

Any of a number of other formats can be used, including ...

  (2√30)cis(-120°)

  (2√30; -120°)

  (2√30; -2π/3)

  2√30·e^(i4π/3)

Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).

__

At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)

6 0
3 years ago
According to government data, the probability that a woman between the ages of 25 and 29 was never married is 40%. in a random s
ddd [48]
The probability of finding 2 never married
10c2*0.4^2*0.6^8=
the probability of finding 1 never married
10C1*0.4*0.6^9=
the probability of finding 0 never married
10C0*0.6^10=

the answer is all the above answers added together.
think you can do the rest of the calculation by yourself. :)

btw nCr=n!/(n-r)!r!
good luck
3 0
3 years ago
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