Answer:
9ab+3a
Step-by-step explanation:
(2a+a)(3b+1)=(3a)(3b+1)
3a(3b+1)
=(3a×3b)+3a×1
=9ab+3a
E is the midpoint so it's HALF of DF
Since it's half that means DE and EF have the same length.
Therefore DE multiplied by 2 is DF.
Considering DF is the full length.
You need at least 2 congruent angles , or 3 proportional sides , or 2 proportional sides and 1 congruent angle to prove that 2 triangles are similar.
I presume that there should be a picture attached to this question , but if you only have 1 side in proportion ( x ) , you cannot prove the similarity of two triangles.
But if there already were two proportional sides or 1 proportional side and one congruent angle , you can prove they are similar if x = 48
Hope it helps
Answer:
45.2
Step-by-step explanation:
You would plug in the probelm would be 3(30+8) = 2×30 -6
