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ser-zykov [4K]
3 years ago
15

Solve the equation 15x+2=45x+4

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0
15x + 2 = 45x + 4

Subtract 2 from both sides, as well as subtracting 45x from both sides.

15x - 45x = 4 - 2

-30x = 2

Divide both sides by -30.

x = 2/-30

x = - 1/15

~Hope I helped!~
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  (a)  26 units

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Step2:eliminate the radicals on the left hand side

Raise both sides to the second power

√x+3)^2=(√2x-1-2)^2

After squaring

x+3=2x-1+4-4-4√2x-1

Step3:get the remaining radicals by itself

x+3=2x-1+4-4√2x-1

Isolate radical on the left hand side

4√2x-1=-x-3+2x-1+4

4√2x-1=x

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Raise both side to the second power

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After squaring

32x-16=x^2

Step 5:solve the quadratic equation

x^2-32x-16

This equation has two real roots

x1=32+√960/2=31.4919

x2=32-√960/2=0.5081

Step6:check that the first solution is correct

Put in 31.4919 for x

√31.4919+3=√2•31.4919-1-2

√34.492=5.873

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Step7:check that the second solution is correct

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Put in 0.5081 for x

√0.5081+3=√2•0.5081-1-2

√3.508=-1.873

1.873#-1.873

One solution was found

x=31.4919

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