Answer: " 
yd² " .
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The area of the square is: " yd² " .
or; write as: " 0.25 yd² " .
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Explanation:
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A "square", by definition, is a quadrilateral and a rectangle, with 4 (four) equal sides and 4 (four) equal angles.
The formula for the area of a square is:
" A = s² " ;
in which: " A = area of the square" ;
(in " square units "; in our case, " square yards " ;
or, write as: " yd² " .
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" s = side length = " 1/2 yd " ; {given} .
______________________________________________________
To find the "Area, "A" ; of the square, which is what the question asks:
→ We plug in the given / known values into the formula, & solve:
→ " A = s² " ;
→ A = (1/2 yd)² ;
= (1/2)² * yd² ;
= (1/2) * (1/2) * yd² ;
= (1 * 1) / (2 * 2) * yd² ;
= " 1/4 yd² " .
______________________________________________________
Answer: " yd² " .
______________________________________________________
The area of the square is: " yd² " .
or; write as: " 0.25 yd² " .
______________________________________________________
______________________________________________________
The area of the square is: "
or; write as: " 0.25 yd² " .
______________________________________________________
Explanation:
______________________________________________________
A "square", by definition, is a quadrilateral and a rectangle, with 4 (four) equal sides and 4 (four) equal angles.
The formula for the area of a square is:
" A = s² " ;
in which: " A = area of the square" ;
(in " square units "; in our case, " square yards " ;
or, write as: " yd² " .
______________________________________________________
" s = side length = " 1/2 yd " ; {given} .
______________________________________________________
To find the "Area, "A" ; of the square, which is what the question asks:
→ We plug in the given / known values into the formula, & solve:
→ " A = s² " ;
→ A = (1/2 yd)² ;
= (1/2)² * yd² ;
= (1/2) * (1/2) * yd² ;
= (1 * 1) / (2 * 2) * yd² ;
= " 1/4 yd² " .
______________________________________________________
Answer: "
______________________________________________________
The area of the square is: "
or; write as: " 0.25 yd² " .
______________________________________________________