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kvv77 [185]
3 years ago
14

Two Technicians are discussing ShopKey Pro. Technician

Computers and Technology
1 answer:
Vlada [557]3 years ago
3 0

Answer:

Technician A is correct

Explanation:

Contact us is the most common term used in online applications such as in websites, mobile/android application to search contact information. People mostly scanning the “contact us” page to find the contact information, if they want to contact the company or organization.

Why technician A is correct.

Technician A is correct because people always try to find the “Contact us” page to find contact information for asking questions, to provide feedback, or any suggestion if they want to provide. It is hard for people to find contact information to provide feedback or give an idea to improve the ShopKey version in “support” heading under the “help” section. Because people are more inclined to search such information in the “Contact us” page rather than exploring the website to find such contact.

Why technical B is not correct

When people want to provide feedback, ask a question or suggest a new idea, they mostly prefer to search for information in the contact us pages. An ordinary user, who has no knowledge of website management or website hierarchy, search contact information in the “Contact us” page rather than searching in support or in the help section.

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Your answer is choice B, Compound Machine.
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Which would cause a decrease in the quantity of computers supplied?
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Answer:The French and Dutch settlements differed from the Spanish colonies in that they were created mainly to trade and develop industries, while the Spanish were primarily concerned with gold and silver excavation, and then later with sugar exportation.

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What is a true job in the information age?​
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2 years ago
Consider sending a 2400-byte datagram into a link that has an mtu of 700 bytes. suppose the original datagram is stamped with th
Feliz [49]

Explanation:

Let, DG is the datagram so, DG= 2400.

Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.

Let, M is the MTU so, M=700.

Let, IP is the IP header so, IP= 20.

Let, id is the identification number so, id=422

Required numbers of the fragment = [\frac{DG-IP}{M-IP} ]

Insert values in the formula = [\frac{2400-20}{700-20} ]

Then,        = [\frac{2380}{680} ] = [3.5]

The generated numbers of the fragment is 4

  • If FV = 1 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=0 and F=1.
  • If FV = 2 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=85(85*8=680 bytes) and F=1.
  • If FV = 3 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=170(170*8=1360 bytes) and F=1.
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3 0
3 years ago
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