Question

A parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the equation of the parabola.

Answer 1

Answer:

f(x) = -3/2(x - 4)² + 6

Step-by-step explanation:

f(x) = a(x - h)² + k, where (h, k) is the vertex

vertex is (4, 6), point (2, 0)

0 = a(2 - 4)² + 6

0 = 4a + 6

-6 = 4a

-3/2 = a

f(x) = -3/2(x - 4)² + 6