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Ann [662]
3 years ago
13

A parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

equation of the parabola.
Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

f(x) = -3/2(x - 4)² + 6

Step-by-step explanation:

f(x) = a(x - h)² + k, where (h, k) is the vertex

vertex is (4, 6), point (2, 0)

0 = a(2 - 4)² + 6

0 = 4a + 6

-6 = 4a

-3/2 = a

f(x) = -3/2(x - 4)² + 6

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Point C is the midpoint of a segment AB . What are the coordinates of point B, if: A(–1, 3), C( 1, –1)
a_sh-v [17]

Answer:

(3,-5)

Step-by-step explanation:

To find the x coordinate of the  midpoint, add the  x coordinates together and divide by 2

The x coordinate is

(x1+x2)/2

We know one point and the midpoint

( -1+x)/2 = 1

Multiply by 2

-1 +x = 2

Add 1

x =2+1

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To find the y coordinate of the midpoint, add the  y coordinates together and divide by 2

The y coordinate is

(y1+y2)/2

We know one point and the midpoint

(3+y)/2 = -1

Multiply by 2

3+y = -2

Subtract 3

y = -2-3

y =-5

The other endpoint is (3,-5)

5 0
3 years ago
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I dont know how to find the answer
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