A parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the
equation of the parabola.
1 answer:
Answer:
f(x) = -3/2(x - 4)² + 6
Step-by-step explanation:
f(x) = a(x - h)² + k, where (h, k) is the vertex
vertex is (4, 6), point (2, 0)
0 = a(2 - 4)² + 6
0 = 4a + 6
-6 = 4a
-3/2 = a
f(x) = -3/2(x - 4)² + 6
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