Find the product (x+2y)(3x+3y)
Help please!
2 answers:
(x+2y)(3x+3y)
Multiply the brackets together
(x)(3x)=3x^2
(x)(3y)=3xy
(2y)(3x)=6xy
(2y)(3y)=6y^2
3x^2+3xy+6xy+6y^2
Answer: 3x^2+9xy+6y^2
3x^2 + 3yx + 6xy +6y^2.
= 3x^2 + 6y^2 + 9 xy
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