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ratelena [41]
3 years ago
12

What does x equal in: 5x-2+x=9+3x+10

Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0
5x-2+x=9+3x+10

therefore, x = 7
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Help quickly please!!!
sineoko [7]

Answer:

M= -2

B=1

Step-by-step explanation:

<u><em>Y-intercept</em></u><em> is the point where the line crosses through the y line, so you can clearly see that that point is (0,1) we only write the y value because for a y intercept the x value will always be zero</em>

<em><u>Slope</u></em> <em>is the rise over run, meaning how much the y value changes over how much the x value changes, so for the two points we use our formula:</em>

\frac{y1-y2}{x1-x2}

<em>So now input how much it changes by adding the numbers from each coordinate:</em>

\frac{(-3)-(1)}{(2)-(0)}

<u>Simplify:</u>

<u />\frac{-4}{2}<u />

<em>But we write it as:</em>

-4/2

<em>This is because this looks more like division</em>

<u>Divide:</u>

-4/2=-2

So, your slope is <em><u>-2</u></em> and the y- intercept is <em><u>1</u></em>

I hope this helps u pls give a brainliest and a thx ;)

7 0
3 years ago
As part of a class project, a university student surveyed the students in the cafeteria lunch line to look for a relationship be
Musya8 [376]

Answer:

27%

Step-by-step explanation:

6 0
3 years ago
Help with solving simulatenous equations with 1 quadratic . question attached
yuradex [85]

Answer:

x = 1/2, y = 17/2

x = -3, y = 12

7 0
3 years ago
Read 2 more answers
Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
insens350 [35]

Answer:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

x -> -2^{-} Say x = -3

p(x) = \frac{(x -3)(x + 1)}{x+2}

p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

x->-2^{-}, p(x)->-\infty

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: x>-2

Say x = -2.1

p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

6 0
3 years ago
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably norma
Nataliya [291]

Answer:

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4  if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

n_{1}=n_{2}=12\\t-stat=-1.4

Compute the degrees of freedom as follows:

\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)

   =\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

P(t_{df}

                      =P(t_{11}>1.4)\\\\=0.095

*Use a <em>t</em>-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

8 0
3 years ago
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