A) Isolate y in both inequalities
1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3
B) Draw the lines for the following equalities:
1) y = 4 - x
2) y = 2x - 3
C) Shade the regions of solutions
1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3
The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3
Answer:
46
Step-by-step explanation:
The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.
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<h3>Pythagorean theorem</h3>
The relation between the leg lengths (a, b) and the hypotenuse (c) is ...
c² = a² +b²
Solving for b gives ...
b = √(c² -a²)
<h3>application</h3>
In this problem, we have c=55 and a=30. Then the width of the TV is ...
b = √(55² -30²) = √(3025 -900) = √2125
b ≈ 46.098
The width of the TV is about 46.
For this case what you need to know is that the original volume of the cookie box is:
V = (w) * (l) * (h)
Where,
w: width
l: long
h: height.
We have then:
V = (w) * (l) * (h) = 48 in ^ 3
The volume of a similar box is:
V = (w * (2/3)) * (l * (2/3)) * (h * (2/3))
We rewrite:
V = ((w) * (l) * (h)) * ((2/3) * (2/3) * (2/3))
V = (w) * (l) * (h) * ((2/3) ^ 3)
V = 48 * ((2/3) ^ 3)
V = 14.22222222 in ^ 3
Answer:
the volume of a similar box that is smaller by a scale factor of 2/3 is:
V = 14.22222222 in ^ 3
Answer: 9 is true, 10 is false
Step-by-step explanation:
The key to these problems is to make sure the sequence of the letters is equal: 10 would be correct if they said DF ≅XZ
