Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
Answer:
c cuh
Step-by-step explanation:
(idk the answer)
Answer:
4
Step-by-step explanation:
Given that:
Total yards of satin bought by Maddie =
yards
Number of yards required make one ribbon =
yards
To find:
Number of complete bows that can be made ?
Solution:
First of all, let us learn about converting the mixed fraction to fractional form.
Formula:

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

One hair bow requires
yards of ribbon.
Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.
Answer is:

4 hair bows can be made.
Answer:
15
Step-by-step explanation:
4 x __ = 12
the blank would be 3, once you did it on one side you have to do it on the other side too
5 x 3 = 15
Another way you can do it is by...
= 
solve for x (cross multiply)