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larisa [96]
3 years ago
11

Derek is going to lay grass in a

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

Step-by-step explanation:

i'd say either 29 1/6 or 32.53

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A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
Q5. Find the simple interest on $950 at 6% per annum for three years.
sveticcg [70]

Answer:

$171

Step-by-step explanation:

=PRN

950×0.06×3

hope this helps and makes sense :))

3 0
3 years ago
Read 2 more answers
Convert 2 3/4 to a decimal number
Solnce55 [7]

Answer:2.75

Step-by-step explanation:

4 0
3 years ago
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Evaluate. Use p = 3, x = 4 <br><br> px^2<br><br> help pls i am giving brainliest
luda_lava [24]

Answer:

144

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which equation represents the formula for the general term, gn, of the geometric sequence 3, 1, 1/3, 1/9, . . .?
dedylja [7]

Answer:

Explicit form: g_n=3(\frac{1}{3})^{n-1}

Recursive form: g_n=\frac{1}{3}g_{n-1} with g_1=3.

Step-by-step explanation:

The first term is 3 and we are dividing by 3 each time.

Another way to say we are dividing by 3 each time is to say we are multiplying by factors of 1/3.

If the first term is a and r is the common ratio then the geometric sequence in explicit form is:

a_n=a(r)^{n-1}

g_n=3(\frac{1}{3})^{n-1}

The recursive form for a geometric sequence is a_n=ra_{n-1} with a_1=a where r is the common ratio and a is the first term.

So the recursive form for our sequence is g_n=\frac{1}{3}g_{n-1} with g_1=3.

6 0
3 years ago
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