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faust18 [17]
3 years ago
11

A construction company has to complete a project no later than 4 months from now or there will be significant cost overruns. The

manager of the construction company believes that there are four possible values for the random variable X, the number of months from now it will take to complete this project: 2, 2.5, 3, and 3.5. It is currently believed that the probabilities of these four possibilities are .1, .6, .2, and .1, respectively. What is the probability that the project was completed sooner than expected
Mathematics
1 answer:
saul85 [17]3 years ago
8 0

Answer:

The probability that the project was completed sooner than expected = 1

Step-by-step explanation:

Given four different variables:

X =(2, 2.5, 3, 3.5)

The probabilities of these variables are 0.1, 0.6, 0.2, 0.1 respectively.

Therefore,

P(X = 2) = 0.1

P(X = 2.5) = 0.6

P(X = 3) = 0.2

P(X = 3.5) = 0.1

For this project to be completed sooner than expected, it should be completed before 4 months.

I.e: P(X<4)

Therefore

P(X<4) = P(X=2)+P(X=2.5)+P(X=3)+P(X=3.5)

P(X<4) = 0.1 + 0.6 + 0.2 + 0.1

PX<4) = 1

The probability that the project was completed sooner than expected is 1.

Since it has a probability of 1, it is certain the job was completed sooner than expected.

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Step-by-step explanation:in standard form y= ax+b

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4 0
3 years ago
1 7/11 divided 2 1/2 <br> Show work if you can :)
Dmitry_Shevchenko [17]
You can say 1 and 7/11 is 18/11 and 2 and 1/2 is 5/2 so : 
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i hope this is helpful 
have a nice day 
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4 years ago
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4 years ago
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