you have to take 51 plus 11 and add it up. then your answer should be 62 degrees different.
In probability, problems involving arrangements are called combinations or permutations. The difference between both is the order or repetition. If you want to arrange the letters regardless of the order and that there must be no repetition, that is combination. Otherwise, it is permutation. Therefore, the problem of arrange A, B, C, D, and E is a combination problem.
In combination, the number of ways of arranging 'r' items out of 'n' items is determined using n!/r!(n-r)!. In this case, you want to arrange all 5 letters. So, r=n=5. Therefore, 5!/5!(505)! = 5!/0!=5!/1. It is simply equal to 5! or 120 ways.
Answer:
Option (C)
Step-by-step explanation:
From the picture attached,
Two lines 'h' and 'k' are the parallel lines and a transversal 'n' is intersecting these parallel lines at two distinct points.
By the theorem of alternate interior angles, angle 8 and angle 11 will be equal in measure.
∠8 ≅ ∠11 [Alternate interior angles]
m(∠8) = m(∠11) = 118°
Therefore, Option (C) will be the answer.
3.225
to check just find 10% of 21.50 (2.15) and 5% of 21.50(1.075)
Answer:
95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college
(0.4958 , 0.7041)
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the sample size 'n' = 85
The sample proportion

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

<u><em>Step(ii):-</em></u>
Given that the level of significance
α = 0.05
Z₀.₀₅ = 1.96

(0.6 - 0.104138 , 0.6 +0.104138)
(0.4958 , 0.7041)
<u><em>Final answer:-</em></u>
95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college
(0.4958 , 0.7041)