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alisha [4.7K]
3 years ago
10

Please help me with this question. Thank you!

Mathematics
1 answer:
Drupady [299]3 years ago
3 0
F=-4+6g
tell me if I'm wrong cuz I'm not that good at math but I wanted to try the question
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During a two-hour period, the temperature in a city dropped from a high of 51°F to a low of −11°F. What was the range of the tem
Likurg_2 [28]

you have to take 51 plus 11 and add it up. then your answer should be 62 degrees different.

6 0
3 years ago
How many ways are there to arrange the first five letters of the alphabet?
Nonamiya [84]
In probability, problems involving arrangements are called combinations or permutations. The difference between both is the order or repetition. If you want to arrange the letters regardless of the order and that there must be no repetition, that is combination. Otherwise, it is permutation. Therefore, the problem of arrange A, B, C, D, and E is a combination problem.

In combination, the number of ways of arranging 'r' items out of 'n' items is determined using n!/r!(n-r)!. In this case, you want to arrange all 5 letters. So, r=n=5. Therefore, 5!/5!(505)! = 5!/0!=5!/1. It is simply equal to 5! or 120 ways.
6 0
3 years ago
Read 2 more answers
Geometry
satela [25.4K]

Answer:

Option (C)

Step-by-step explanation:

From the picture attached,

Two lines 'h' and 'k' are the parallel lines and a transversal 'n' is intersecting these parallel lines at two distinct points.

By the theorem of alternate interior angles, angle 8 and angle 11 will be equal in measure.

∠8 ≅ ∠11 [Alternate interior angles]

m(∠8) = m(∠11) = 118°

Therefore, Option (C) will be the answer.

7 0
3 years ago
After the 15% sales tax the jeans were $21.50. How much did the jeans cost before the sales tax was added? Round to the nearest
Ilya [14]

3.225

to check just find 10% of 21.50 (2.15) and 5% of 21.50(1.075)

6 0
3 years ago
Read 2 more answers
A simple random sample of 85 students is taken from a large university on the West Coast to estimate the proportion of students
ahrayia [7]

Answer:

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the sample size 'n' = 85

The sample proportion

            p = \frac{x}{n} = \frac{51}{85} = 0.6

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(p^{-} -Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.05} \sqrt{\frac{p(1-p)}{n} })

<u><em>Step(ii):-</em></u>

Given that the level of significance

α = 0.05

Z₀.₀₅ = 1.96

(0.6 -1.96 \sqrt{\frac{06(1-06)}{85} } , 0.6 +1.96 \sqrt{\frac{0.6(1-0.6)}{85} })

(0.6 - 0.104138 , 0.6 +0.104138)

(0.4958 , 0.7041)

<u><em>Final answer:-</em></u>

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

6 0
3 years ago
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