Answer:
1010 0111 1101 1111
Explanation:
A = 10 in decimal = 1010 in binary
7 = 7 in decimal = 0111 in binary
D = 13 in decimal = 1101 in binary
F = 15 in decimal = 1111 in binary
Therefore 0xA7DF = 1010 0111 1101 1111 in binary
Answer:
Install recommended updates.
Explanation:
To resolve this exploit the company has to install recommended updates. Since their encryption is prone or unsecured so to have better encryption or more secured encryption they have to install recommended updates.Since log files getting transferred over this channel so the company would not want to someone mess with their log files.
The least common multiple (LCM) of 78, 90, and 140 is: 16,380
78 × 210 = 16,380
90 × 182 = 16,380
140 × 117 = 16,380
Answer:
You can use the pop() method to remove specific elements of a list. pop() method takes the index value as a parameter and removes the element at the specified index. Therefore, a[2] contains 3 and pop() removes and returns the same as output.
Explanation:
Hope it helps you!
