Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.
Answer:
(2, 3).
Step-by-step explanation:
3x+2y=12
6x+3y=21 Multiply the first equation by 3 and the second by 2:
9x + 6y = 36
12x + 6y = 42 Subtract:
-3x = -6
x = -6/-3 = 2.
Plug x = 2 into the first equation:
3(2) + 2y = 12
2y = 12 - 3(2)
2y = 6
y = 3.
9/10 - 5/10
because the denominators are the same you keep it and just subtract the numerators
=4/10
This can be reduced to 2/5
the axis of symmetry is x=2
Answer:
confused what graph are using
Step-by-step explanation:
