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sdas [7]
3 years ago
6

How do I write an inequality for this graph? Dint mind the other ones just number 5

Mathematics
2 answers:
qwelly [4]3 years ago
8 0
X <-7 probably??????????
Strike441 [17]3 years ago
4 0
X <-7 nnnsnsjssjjsjajajaj
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How many solutions does 8 + x/6 = x/6 - 4 + 5x/12 have?
vladimir2022 [97]
Am not sure but I think is c
6 0
3 years ago
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Find the MAD for this set of data
diamong [38]

Using it's concept, it is found that the Mean Absolute Deviation for this set of data is of 0.8.

<h3>What is the mean absolute deviation of a data-set?</h3>

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations. Hence, it is the sum of deviations divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

In this problem, there are 10 observations, and the sum of the deviations is of 1 + 3 + 1 + 1 + 1 + 1 = 8. Hence the MAD is given as follows:

MAD = 8/10 = 0.8.

More can be learned about the Mean Absolute Deviation at brainly.com/question/3250070

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7 0
3 years ago
1*11<br> *<br> What is 11x11
Vika [28.1K]
11x11 is 121 , if that is what ur asking
7 0
4 years ago
Read 2 more answers
Please help it would be much appreciated.
yulyashka [42]
100
explanation: those two angles are supplementary which add up to be 180.
6 0
3 years ago
Michael breeds chickens and ducks. Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44 chickens and 36
Radda [10]

Answer:

a chicken cost $4

a duck cost $11.66

Step-by-step explanation:

Let the cost of one chicken be x

then cost of 50 chicken = 50x

cost of one duck be y

cost of 30 ducks = 30y

It is given that  50 chickens and 30 ducks cost $550

thus

50x+30y = 550

dividing LHS and RHS by 10 we have

50x/10+30y/10 = 550/10

=>5x+3y = 55 ____________________(1)

_________________________________

for this month we have calculation as given below

cost of 44 chicken = 44x

cost of 36 ducks = 36y

It is given that  44 chickens and 36 ducks cost $532

thus

44x+36y = 532

dividing LHS and RHS by 4 we have

44x/4+36y/4 = 532/4

=>11x+9y = 133  ______________2

__________________________________

we have equation

5x+3y = 55 ____________________(1)

11x+9y = 133  ______________2

multiplying equation 1 by 3 on LHS and RHS we have.

(note: multiplication with3 is done to transform 3y into 9y

so that y can be removed from equation)

5x*3+3y*3 = 55*3

=> 15x+9y = 165  ___(3)

subtracting equation 3 from equation 1 we have

15x+9y = 165

-(11x+9y )= 133

15x +9y -11x -9y = 165 - 133

=> 4x = 32

=> x = 32/4 = 4

5x+3y = 55

=>5*4 +3y = 55

=>20+ 3y = 55

=>3y = 55-20 = 35

=>y = 35/3 =11.66

Thus,a chicken cost $4

a duck cost $11.66

5 0
3 years ago
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