Order of operations 5-2(5-27)+5
1 answer:
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Answer:
Use F.O.I.L, (First Outer Inner Last) to multiply. Start with -3x^y * 5xy^2
Start with similar terms
Move onto the xy portion of the problem
Start with similar terms
Combine the two together
The answer is Option A
Answer:
The area of the trapezoid is 15 square miles.
Step-by-step explanation:
There are two ways you can solve for the area of a trapezoid.
The first way is to memorize the formula for a trapezoid:
where b1 and b2 are the bases of the trapezoid;
h is the height of the trapezoid.
Simply substitute the values you have from the problem. b1 is 2 miles, b2 is 3 miles, and h is 6 miles.
(Note that b1 and b2 are interchangeable, so do not worry about which value for a base of the trapezoid should be b1 or b2.)
A = (1/2)*(2mi + 3mi)*(6mi)
Simplify.
A = (3mi)(5mi) = 15 sqare miles
The second way is to split the area of the trapezoid into smaller areas. We know that this trapezoid is made up of two triangles and a rectangle. So let it be that! The area of the trapezoid is the area of the two triangles plus the area of the rectangle.
A = 2*(1/2)(b)(h) + (b)(h)
The base of the triangle is 1/2 mile and the height of the triangle is 6 miles. The base of the rectangle is 2 miles and the height of the rectangles is 6 miles.
A = 2*(1/2)*(1/2mi)*(6mi) + (2mi)(6mi)
Simplify.
A = 3 square miles + 12 square miles = 15 square miles.
Answer:
The snail is 27 inches from the rock.
Step-by-step explanation:
The given equation is d = 3t
d is the distance in inches that a snail is from a certain rock
and t is the time in minutes.
In order to find the distance of snail from the rock in 9 minutes, we substitute t = 9 in the given equation.
On substituting, t=9
Therefore, the snail is 27 inches from the rock.