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forsale [732]
3 years ago
15

You are planning a trip to Japan in the fall. You estimate that for two weeks, you will need $5,263 (This includes airfare, room

and board, daily expenses, and travel). Your gross biweekly income is $1,626 for one pay period. For each pay period, you pay 6.2% Social Security, 1.45% Medicare, $85 in state taxes, $225 in federal taxes, and $775 in regular expenses. You save for 14 consecutive, biweekly pay periods. How much will you have saved up and will you have saved enough to visit Japan for two weeks? Round all your answers to the nearest dollar. a. $2,014; no c. $5833; yes b. $5,861; yes d. $8,092; yes
Mathematics
1 answer:
Gemiola [76]3 years ago
4 0
The income that you can save from each biweekly paycheck is
.. $1626 -6.2%*1626 -1.45%*1626 -85 -225 -775 = $416.61

After 14 pay periods, you will have saved
.. 14*$416.61 = $5832.54

This is more than your estimated trip requirement.

c. $5833; yes
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Elias and Mark together have $756.80. Elias has $489.50. Write and solve an addition equation to determine how much money Mark (
Degger [83]

Answer:

489.5 + m = 756.80 (the amount elias has, added to marks is equal to the total

(756.8- 489.5 = 267.30 which is the amount mark has.)

m= 267.3

the last option is the correct option

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck
Nimfa-mama [501]
\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}
\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}

Now, isolate the variables, so you can integrate.
(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}
\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}
2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C


4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C
y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C
(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C
(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C


y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}
y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}

At x = 1, y = 0.
0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}
-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}

4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0
\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}


4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C
0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C
C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}
C = -\frac{\pi}{2}

\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}
6 0
3 years ago
I need help answering
Sever21 [200]
Rupees 937.36

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4 0
3 years ago
Fran reads 54 pages per hour Darnell reads 60 pages per hour if they both read for 2.5 hours how many more pages will Darnell Re
spin [16.1K]
Hey You! Here's How To Solve This Question:


STEP 1:

60 × 2.5 = 150


STEP 2:

54 × 2.5 = 135


STEP 3:

150 - 135 = 15


So, Darnell read 15 more pages than Fran.

I Really Hope My Answer Helped You!
7 0
3 years ago
Find the slope using the formula, (-11,3) and (-7,5)
Flura [38]

Answer:

y = 1/2x+8.5

Step-by-step explanation:

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7 0
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