Answer:
$0 < p ≤ $25
Step-by-step explanation:
We know that coach Rivas can spend up to $750 on 30 swimsuits.
This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:
C ≤ $750
Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:
C = 30*p
Then we have the inequality:
30*p ≤ $750.
To find the possible values of p, we just need to isolate p in one side of the inequality.
So we can divide both sides by 30 to get:
(30*p)/30 ≤ $750/30
p ≤ $25
And we also should add the restriction:
$0 < p ≤ $25
Because a swimsuit can not cost 0 dollars or less than that.
Then the inequality that represents the possible values of p is:
$0 < p ≤ $25
-3x + y = 1 ............. the general form is y= mx +b .................y = 1 + 3x
...........................
Y = 3x + 1
Answer: 3.5
Step-by-step explanation: divide 49 by 14
There was $800 deposited at 9% interest and $400 deposited at 4% interest.
The formula for simple interest is I = prt. Using our information we have:
88 = x(0.09)(1) + (1200-x)(0.04)(1)
88 = 0.09x + 48 - 0.04x
88 = 0.05x + 48
Subtract 48 from both sides:
88 - 48 = 0.05x + 48 - 48
40 = 0.05x
Divide both sides by 0.05:
40/0.05 = 0.05x/0.05
x = 800
1200 - x = 400
28÷2＝14
The bus makes 14 stops every hour
14×3＝42
The bus makes 42 stops in 3 hours
Hope my answer helped u :)
