(x-3)(x-5)
i hope this helps :)
Answer:
A
Step-by-step explanation:
The answer: the second one y= -2x+7
The impulse that was produced by this aircraft jet engine is 5,400 Ns.
<u>Given the following data:</u>
To determine the impulse that was produced by this aircraft jet engine:
<h3>How to calculate
impulse.</h3>
Mathematically, impulse is given by this formula:

<u>Where:</u>
- F is the force or thrust.
- t is the time measured in seconds.
Substituting the given parameters into the formula, we have;

Impulse, I = 5,400 Ns.
Read more on impulse here: brainly.com/question/16750406
Answer: The answers are (a) 40 cm and (b) 
Step-by-step explanation: The calculations are as follows:
(a) See the figure (a). As given in the question, A circle with centre 'O' circumscribes a triangle ABC with BC = 20 cm and ∠BAC = 30°. We need to find the diameter DC of the circle.
Let us draw BD. Now, ∠BAC and ∠BDC are angles on the same arc BC, so we have
∠BAC = ∠BDC = 30°.
Also, ∠CBD = 90°, since it stands on the diameter DC. So, ΔBCD will be a right angled triangle.
We can write

Thus, the diameter of the circle = 40 cm.
(b) See the figure (b).
As given in the question, A circle with centre 'O'' circumscribes a triangle DEF with EF = 4.6 inches and diameter GF = 12.4 in.. We need to find the angle EDF.
Let us draw GE. Now, ∠EGF and ∠EDF are angles on the same arc EF, so we have
∠EGF = ∠EDF = ?
Also, ∠GEF = 90°, since it stands on the diameter GF. So, ΔGEF will be a right angled triangle.
We can write

Thus,
