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3 years ago

6

Derrico is building a holding pen for his dogs. The rectangular holding pen is 14.8 feet wide by 8.9 feet long. About how many f

eet of fencing will he need to build the sides of this holding pen?

2 answers:

son4ous [18]3 years ago

8 0

Answer:

11

Step-by-step explanation:

Dmitriy789 [7]3 years ago

3 0

It’s 6

Step by step explanation:

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Pls help answer this soon!!!!!

vladimir1956 [14]

13a) y = 0.45x

13b) 52 * 0.45 = 23.4

13c) I will let u figure this one out

7 0

3 years ago

Read 2 more answers

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

2 years ago

Write a formula that will yield the nth term of the sequence: 3,-2,-7,-12

RUDIKE [14]

Answer:

-5n + 8

Step-by-step explanation:

<u>1. What is the difference?</u>

The sequence goes down by 5. This means that the formula will have -5n in it.

<u>2. Work out the term before the first term.</u>

The first term is 3, and we know that the sequence goes up by 5. So, to get the term before 3 we would add 5.

3 + 5 = 8 Remember, this is positive 8. (+8)

<u>3. Put that term at the end of the equation. </u>

We have -5n already and we just worked out the term before the first one which is positive 8 - so put that at the end of the equation.

-5n + 8 This is our answer!

Just to prove it works:

<em>Substitute: n = term</em>

Lets see if we can get the 3rd term which is -7. (n = 3)

-5(3) + 8

-15 + 8 = -7

See, it works!

8 0

3 years ago

For Tran Please help is appreciate it

Ostrovityanka [42]

Answer:

A = 38°

Step-by-step explanation:

We are going to use cosine law to find angle A where

a = 4.7

b = 3.9 m

c = 2.9 m

${c}^{2} = {a}^{2} + {b}^{2} - 2ab \cos( \alpha )$

or

$\cos( \alpha ) = \frac{ {a}^{2} + {b}^{2} - {c}^{2} }{2ab}$

cos A = [(4.7)^2 + (3.9)^2 - (2.9)^2]/2(4.7)(3.9)

= 28.89/36.66

= 0.788

A = arccos(0.788) = 38°

6 0

3 years ago

If x+ay =b and<br> ax-by=c <br> Then find out x , y . (with process)

n200080 [17]

Answer:

The solution of the given system of equations is,

$x=\frac{b^2+ac}{a^2+b};\; y=\frac{ab-c}{a^2+b}$

Step-by-step explanation:

The given equations are :

<em>x</em> + a<em>y</em> = b .......(1)

a<em>x</em> - b<em>y</em> = c .......(2)

We will use 'Substitution Method' to solve the given system of equations.

In this method, we will find out the value of either of the two variables that is '<em>x</em>' and '<em>y</em>' from one of the two equations in terms of the another variable and then substitute that value in the other equation to find the value of the another variable.

Now, we will be finding out the value of '<em>x</em>' in terms of '<em>y</em>' from equation (1) and then substitute it in the equation (2).

Consider the equation (1), that is,

<em>x</em> + a<em>y</em> = b ⇒ <em>x</em> = b - a<em>y</em> ........(3)

Substitute the value of '<em>x</em>' from (3) in (2), we get

a(b - a<em>y</em>) - b<em>y</em> = c

⇒ab - a²<em>y</em> - b<em>y</em> = c

⇒-a²<em>y</em> - b<em>y</em> = c - ab

⇒-<em>y</em>(a²+b) = c - ab

⇒<em>y</em>(a²+b) = ab - c

$\implies y=\frac{ab-c}{a^{2}+b}$

Now, substituting the above value of '<em>y</em>' in equation (3), we get

$x=b-a(\frac{ab-c}{a^2+b})$

$\implies x=\frac{b(a^2+b)-a(ab-c)}{a^2+b}$

$\implies x=\frac{a^2b+b^2-a^2b+ac}{a^2+b}$

$\implies x = \frac{b^2+ac}{a^2+b}$

Hence, the solution of the given system of equations is,

$x = \frac{b^2+ac}{a^2+b} ;\; y = \frac{ab-c}{a^2+b}$

5 0

3 years ago