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tester [92]
1 year ago
10

Identify the excluded values of this product. Then rewrite the product in simplest form.

Mathematics
1 answer:
lara [203]1 year ago
8 0

\frac{6 {y}^{2} + 18y - 60 }{3 {y}^{2} - 12y }  \times  \frac{ {y}^{2} - 16 }{ {y}^{2}  + 2y - 8}  \\  \\  \frac{ {6y + 30y - 12y - 60}^{2} }{3y(y - 4)}  \times  \frac{ {(y)}^{2} - ( {4)}^{2}  }{ {y}^{2} + 4y - 2y - 8 }  \\  \\  \frac{6y(y + 5) - 12(y + 5)}{3y(y - 4)}  \times  \frac{(y + 4)(y - 4)}{y(y + 4) - 2(y + 4)}  \\  \\  \frac{(6y - 12)(y + 5)}{3y(y - 4)}  \times  \frac{(y + 4)(y - 4)}{(y + 4)(y - 2)}  \\  \\  \frac{6(y - 2)(y + 5)}{3y(y - 2)}  \\  \\  \frac{2(y + 5)}{y} .

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masya89 [10]

Answer:

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Step-by-step explanation:

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5/14 is the answer. I'll do my best bud
Answer↑

Steps↓
Convert 2 1/2 to an improper fraction:
2 + 2+ 1 over 2

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