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marusya05 [52]
3 years ago
6

Put the following equation of a line into slope-intercept form, simplifying all fractions.

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0

Answer:

y=-4x/3-1

Step-by-step explanation:

y=mx+b is point slope form. Subtract 4x from both sides then divide by 3

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The graph of f(x) - 4 is obtained by translating the graph of f(x) 4 units down.
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An oblique prism is created using rhombuses with edge lengths of 25 units. The area of one rhombus is 600 square units. The perp
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A store sells 4 main types of chocolate bars milk chocolate dark chocolate white chocolate and hazelnut chocolate the store empl
sergij07 [2.7K]
Hi there! The answer is A. 252

To find the percentage of the customers who preferred the milk chocolate bar we need to know two things:

First we need to know the total amount of customers, which is 50.
Second we need to know how many of these customers preferred the milk chocolate bar. This bar is preferred by 28 people.

Now we can fill in the following formula, in order to find our percentage:
\% = \frac{part}{total} \times 100 \% = \frac{28}{50} \times 100 \% = 0.56 \times 100 \% = 56 \%

Now we can multiply this percentage by the total amount of chocolate bars which will be bought (which is 450).
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Hence, the answer is A. 252
~ Hope this helps you!
7 0
3 years ago
HELP ME FIND THE PRECENTAGE IT INCREASED PLEASE!
Temka [501]
%change=100(final-initial)/initial

%change=100(7498847290-6672678672)/6672678672

%change=12.38%  (to nearest one-hundredth of a percent)

So the world's population increased by 12.38%.
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%20%20%5Csqrt%7B3x%7D%20%7D%7B1%20%2B%20e%5E%7B2x%7D%20%7D%20" id="TexF
kumpel [21]

~~~~~~~~y = \dfrac{\sqrt{3x}}{ 1+ e^{2x}}\\\\\\\implies \dfrac{dy}{dx} = \dfrac{d}{dx}  \left( \dfrac{\sqrt{3x}}{1+ e^{2x}} \right)\\\\\\~~~~~~~~~~~~=\dfrac{(1 + e^{2x} ) \dfrac{d}{dx} \left(\sqrt{3x} \right) - \left(\sqrt{3x} \right)\dfrac{d}{dx}(1+e^{2x})}{\left( 1+ e^{2x} \right)^2}~~~~~~~~~~~~;[\text{Quotient rule}]\\\\\\~~~~~~~~~~~~=\dfrac{(1+e^{2x}) \cdot \dfrac{1}{2\sqrt{3x}} \cdot 3-\left(\sqrt{3x} \right) \cdot 2 e^{2x}}{(1 + e^{2x})^2}~~~~~~~~~~~~~~~~~~~~;[\text{Chain rule}]\\\\\\

            =\dfrac{\dfrac{\sqrt 3 (1 + e^{2x})}{2\sqrt x} -2e^{2x} \sqrt{3x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\tfrac{\sqrt 3(1 +e^{2x}) - 4x\sqrt 3 e^{2x}}{2\sqrt x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\sqrt 3(1+e^{2x} -4xe^{2x})}{2\sqrt x(1 +e^{2x})^2}

7 0
2 years ago
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