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rodikova [14]
3 years ago
11

According to a recent survey of first-year high school students, 28% chew gum daily. The students were also asked if they had re

cently gotten a cavity filled at the dentist. Of the 47% of first-year students who responded that they had a cavity recently filled, only 39% chewed gum daily. Is chewing gum independent of having a cavity filled recently? Yes, P(Gum) = P(Gum|Cavity). Yes, P(Gum) = P(Cavity|Gum). No, P(Gum) ≠ P(Gum|Cavity). No, P(Gum) ≠ P(Cavity|Gum).
Mathematics
1 answer:
Brut [27]3 years ago
4 0

Answer:

No its not since only 39% if the people who had cavitys had chewed gum regurely

Hope This Helps!!!

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Melissa put her cat, Herman, on a diet and kept track of his weight. At the end of 4 weeks, she recorded Herman's weight change
Sergio [31]

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<h3><u>Solution:</u></h3>

Given that, Melissa put her cat, Herman, on a diet and kept track of his weight.  

At the end of 4 weeks, she recorded Herman's weight change as -4\frac{1}{2} ounces.  

She noticed that he had lost the same amount of weight each week.  

We have to find what is Herman's weight change each week of the diet?

Now, let the weight lost per week be n ounces.

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And we are given that, lost wait is -4\frac{1}{2} ounces

\begin{array}{l}{4 n=-(4 \frac{1}{2}) \text { ounces }} \\\\ {4 n=-(\frac{4 \times 2+1}{2})} \\\\ {4 n=-(\frac{9}{2})} \\\\ {n=-(\frac{9}{8})=-(\frac{8+1}{8})=-1 \frac{1}{8} \text { ounces }}\end{array}

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Therefore, the second graph 'b', is correct!

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