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3 years ago

5

Find the GCF of the following terms. 16xy^3 , 20x^2y^2 , -4x^2y

1 answer:

Ivanshal [37]3 years ago

7 0

$16xy^3=4xy\cdot4y^2\\\\20x^2y^2=4xy\cdot5xy\\\\-4x^2y=4xy\cdot(-x)\\\\GCF(16xy^3;\ 20x^2y^2;\ -4x^2y)=4xy$

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Use your calculator to find an interval of length 0.01 that contains a root. (enter your answer using interval notation.)

allochka39001 [22]

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3 years ago

Nine minus the quotient of two and a number x

Dennis_Churaev [7]

9-2/x is the equation

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3 years ago

Evaluate f(x)=e2x−1+2 when x=3. Give an approximate answer rounded to three decimal places.

olganol [36]

Answer:

f(3) ≈ 17.310

Step-by-step explanation:

e = 2.71828

Step 1: Define

f(x) = e2x - 1 + 2

x = 3

Step 2: Substitute and evaluate

f(3) = e2(3) - 1 + 2

f(3) = 6e + 1

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7 0

3 years ago

Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

<em>This has been shown in (c) above</em>

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3 years ago

You scored a 95% on your math quiz the quiz was out of 60 points how many points did you get

amid [387]

60/100 times by 95 so 57

5 0

3 years ago

Read 2 more answers