F(x) = 3x + 7.....g(x) = 4x - 2
A. (f + g)(x)
3x + 7 + 4x - 2
7x + 5 <====
B. (f * g)(x)
(3x + 7)(4x - 2) =
3x(4x - 2) + 7(4x - 2) =
12x^2 - 6x + 28x - 14
12x^2 + 22x - 14 <===
C. f[g(x)]
3(4x - 2) + 7 =
12x - 6 + 7 =
12x + 1 <===
16-A 18-B 19-D (not 100% sure on 16)
Answer:
m=1/3
Step-by-step explanation:
trust
