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zvonat [6]
3 years ago
10

Evaluate.

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>none</em><em> </em><em>of</em><em> </em><em>these</em><em>.</em>

<em>Answer</em><em> </em><em>is given below with explanations</em><em>. </em>

Step-by-step explanation:

<em>Given</em><em> </em><em>that</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>-2</em><em>.</em><em>5</em>

<em>To</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em>+</em><em>13</em>

<em>Ob</em><em> </em><em>substituting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>given equation</em><em> </em>

<em>we</em><em> </em><em>get</em><em> </em>

<em>=</em><em> </em><em>-2</em><em>.</em><em>5</em><em>+</em><em>13</em>

<em>=</em><em> </em><em>13</em><em> </em><em>-</em><em> </em><em>2</em><em>.</em><em>5</em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>we</em><em> </em><em>can</em><em> </em><em>also</em><em> </em><em>write</em><em> </em><em>like</em><em> </em><em>this</em><em>)</em>

<em>=</em><em> </em><em>10</em><em>.</em><em>5</em>

<em>Therefore</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>+</em><em>13</em><em> </em><em>is</em><em> </em><em>10</em><em>.</em><em>5</em>

<em>HAVE</em><em> </em><em>A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

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Justin says that if the diameter of any circle is 15 feet then its radius must 10
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I know this one give me like 5 minutes
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A porch has the shape of a quarter circle with a diameter of 5 ft. What is the approximate area of the porch, rounded to the nea
GalinKa [24]
Area=pi times radiius^2
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area=19.625 ft^2

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19.6 round up
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