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What are the zeros of the function f, where f(x) = 6x2 - 9x – 6?
2 answers:
Answer:
Step-by-step explanation:
Use the Pythagorean Theorem to find the zeros of 6x² - 9x - 6.
x = [9±√(9²-4(6)(-6))]/[2(6)] = [9±√225]/12 = [9±15]/12 = 2, -½
Answer:
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