Answer:
 and
 and  .
.
Step-by-step explanation:
So I believe the problem is this:

where we are asked to find values for  and
 and  such that the equation holds for any
 such that the equation holds for any  in the equation's domain.
 in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.


As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.




Divide both sides by -10:


Now we have:
 with
 with 
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.




Divide both sides by 10:


So  and
 and  .
.
 
        
                    
             
        
        
        
Answer:
1 /4 plus 3/4 equals 1 one whole cuz the 1 plus 3 4 and the 4/4 thats one 1
Step-by-step explanation:
 
        
             
        
        
        
Answer: (x + 0, y − 4), 180° rotation, reflection over the y-axis.