Answer:
Hello the loop required for your question is missing below is the loop
Loop: lw x1,0(x2)
addi x1,x1, 1
sw x1,0(x2)
addi x2,x2,4
sub x4,x3,x2
bnz x4,Loop
answer : attached below
Explanation:
<u>Show the phases of each instruction per clock cycle for one iteration of the loop </u>
loop length
loop
lw x1,0(x2)
addi x1,x1, 1 values attached below
sw x1,0(x2)
addi x2,x2,4
sub x4,x3,x2
bnz x4,Loop
Attached below are the phases of each instruction per clock cycle for one iteration of the loop
Answer:
C
Explanation:
C seems to be the most logical choice for a "good" choice.
It makes the most sense.
Answer:
2 x 10⁵ bytes per second
Explanation:
Given:
MIPS rate = maximum speed of CPU to execute instructions = 10 million instructions per seconds
number of instructions required to transfer 1 byte using interrupt driven I/O = 50
Maximum number of bytes that can be transferred in 1 second = MIPS rate / number of instructions for 1 byte
=> max number of bytes = 10 million / 50 = 10 x 10⁶ / 50 = 2 x 10⁵
which is less than the maximum transfer rate of memory = 100 million bytes per second
So, maximum data transfer rate during I/O operations by using interrupt-driven I/O is 2 x 10⁵ bytes per second
Answer:
Tables are made up of related records.
Explanation:
Number one is c shouldn’t have to explain pretty simple
