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3 years ago

C. Read and analyze the problem, then solve.

Mathematics

1 answer:

Sliva [168]3 years ago

5 0

Given parameters:

Total length of curtains bought = 20m

She used 8m for the living room

She used 7m for the dining room

unknown:

Quantity used for the kitchen = ?

Solution:

Quantity used for the kitchen = Total length - (living room + dining room)

Input the parameters given solve;

Quantity used for the kitchen = 20 - (8 + 7) = 5m

The length of curtain used for the kitchen is 5m

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Help pleaseeeeeee, I need help

Arlecino [84]

Answer:

15, 60, and 61

Step-by-step explanation:

First we have to find the 3rd side length from 2 side length chosen. So let’s pick 8 meters and 11 meters, to find the third side length we use the Pythagorean theorem: c^2 = a^2 + b^2

c = 11^2 + 8^2 = 121 + 64 = 185 = 13.6

13.6 isn’t one of the answers so we can’t pick 11 & 8. Let’s try 11 & 15:

c = 15^2 + 11^2 = 225 + 121 = 346 = 18.6

18.6 isn’t one of the answers either. Let’s try 15 & 60:

c = 60^2 + 15^2 = 3600 + 225 = 3825 = 61.85

61.85 might be it but let’s try one more just in case:

c = 60^2 + 61^2 = 3600 + 3721 = 7321 = 85.6

Nope! That means 15, 60, and 61 are the answer. I hope this is correct!

5 0

3 years ago

Round 23,421 to the nearest thousand and ten thousand

Ronch [10]

To the nearest thousand is 23,000 and the nearest ten thousand is 20,000

8 0

3 years ago

Read 2 more answers

mrs peters bought 7 1/2 yards of fabric she needs another 4 7/8 yards how many yards of fabric does she need altogether

Nataliya [291]

7 1/2 = 15/2 = 60/8
4 7/8 = 39/8

60/8 + 39/8 = 99/8 = 12 3/8 yards

6 0

3 years ago

Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 4,000,000 and a mean

In-s [12.5K]

Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 19000, \sigma = \sqrt{4000000} = 2000$

The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20179 - 19000}{2000}$

Z = 0.59.

Z = 0.59 has a p-value of 0.7224.

1 - 0.7224 = 0.2776.

0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

6 0

2 years ago

Find the product and simplify your answer. 7a5(-3a4+5a-5)

Alex Ar [27]

$\text{Hey there!}$

$\mathsf{Use\ distributive\ property\ to\ solve}}\\\\\text{The formula is : a(b + c)=a(b)+a(c)=b+ac}\\\\\mathsf{7a^5(-3a^4+5a-5)}\\\\\mathsf{7a^5(-3a^4)=-21a^9}\\\\\mathsf{7a^5(5a)=3a^6}\\\\\mathsf{7a^5(-5)=-35a^5}$

$\boxed{\boxed{\mathsf{Your\ answer: \boxed{\mathsf{-21a^9+35a^6-35a^5}}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

3 0

2 years ago