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3 years ago

13

Choose the graph 12-4×>8

1 answer:

Sergeu [11.5K]3 years ago

8 0

Answer:

-20

Step-by-step explanation:

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Can someone explain the steps to finding the perimeter of a semi-circle? I didn't really understand it during class. Thanks

andriy [413]

We know that the perimeter of a cylinder is 2πr we will find it as we do always. The perimeter will be :
2 pi r
= 2 pi * 20
= 40 pi
Because it says rounded to the nearest tenth the answer will be : 125.6 cm^3
Because we have a half of a cylinder we will just divide the answer we got by 2:
125.6cm^3 /2 =62.8
The answer is 62.8 cm^3

6 0

3 years ago

Use the t-distribution and the sample results to complete the test of the hypotheses. Use a significance level. Assume the resul

Ksenya-84 [330]

Answer:

Test statistic = 1.3471

P-value = 0.1993

Accept the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 4

Sample mean, $\bar{x}$ = 4.8

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2.3

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 4\\H_A: \mu \neq 4$

We use two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.8 - 4}{\frac{2.3}{\sqrt{15}} } = 1.3471$

Now, we calculate the p-value.

P-value = 0.1993

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept it.

3 0

3 years ago

1.What is the value of log3 729?

xxMikexx [17]

I believe the value of log3 729 is 6

3 0

3 years ago

Read 2 more answers

K is no greater than 9?<br><br> Write>,<.

alekssr [168]

Greater than symbol is ">"
But since he mentioned "NO greater than" then it's the opposite of greater than, which means "K" is less than "9"

K<9

4 0

3 years ago

Given: Triangle ABC : triangle ADB. AB =24, AD =16 <br> Find: AC

RoseWind [281]

Answer:

<h2>AC = 36.01</h2>

Step-by-step explanation:

Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.

From ΔADB, AB² = AD²+BD²

Given AB = 24 and AD = 16

BD² = AB² - AD²

BD² = 24²-16²

BD² = 576-256

BD² = 320

BD = $\sqrt{320}$

BD = 17.9

from ΔABC, AC² = AB²+BC²

SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;

(AD+DC)² = AB²+ (BD² + DC²)

Given AD = 16, AB = 24 and BD = 17.9, on substituting

(16+DC)² = 24²+17.9²+ DC²

256+32DC+DC² = 24²+17.9²+ DC²

256+32DC = 24²+17.9²

32DC = 24²+17.9² - 256

32DC = 640.41

DC = $\frac{640.41}{32}$

DC = 20.01

Remember that AC = AD+DC

AC = 16+20.01

AC = 36.01

6 0

3 years ago