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andrew11 [14]
3 years ago
12

Front end round then do the math -1,244+63,794

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0
Hello,

Answer:
= 62,550
Showing Work-1244 + 63794
= 62550

Rounding to Ones Place
= 62550

Faith xoxo
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AleksandrR [38]

Ok so first we find the equation that equals one variable.


2y = -x + 9

3x - 6y = -15


We solve for y.


2y = -x + 9

y = -x/2 + 9/2


Then we plug in this y value into the other equation to keep only one variable so we can solve for it.


3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18


Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.


y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3


Your answer would be (-28/3, -3/18)


Hope this helps!

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Sever21 [200]

Answer:

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Step-by-step explanation:

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<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. 

</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
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This step is perfectly fine. 

In Step 2, \dfrac{d}{dx}(8x) was kept as it is, and \dfrac{d}{dx}(-3) was rewritten as 0 using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.

This step is perfectly fine. 

In Step 3, \dfrac{d}{dx} (8x)  was rewritten as \dfrac{d}{dx}(8) \dfrac{d}{dx}(x) supposedly using the constant multiple rule.

The problem is that according to the constant multiple rule, \dfrac{d}{dx}(8x)&#10; should be rewritten as 8 \dfrac{d}{dx}(x) and not as \dfrac{d}{dx}(8)\dfrac{d}{dx}(x).  

<span>Therefore, Hannah made a mistake in this step.</span>
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Solve each system by substitution. please help me<br> 2x{+y=6<br> x{+y=3
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1. x= 3/Y as a fraction btw

2. Same thing
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