Question

PLEASE HELP ME ASAP!

Answer 1

Ok so first we find the equation that equals one variable.

2y = -x + 9

3x - 6y = -15

We solve for y.

2y = -x + 9

y = -x/2 + 9/2

Then we plug in this y value into the other equation to keep only one variable so we can solve for it.

3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18

Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.

y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3

Your answer would be (-28/3, -3/18)

Hope this helps!

Answer 2

(For this, I'll be using the substitution method.)

So firstly, subtract 9 on each side of the first equation. Your equation will look like this: $2y-9=-x$

Next, flip the signs around in the first equation. Your equation will look like this: $-2y+9=x$

Next, substitute x in the second equation for (-2y+9). From there you can solve for y. $3(-2y+9)-6y=15$

Firstly, foil 3(-2y+9). $-6y+27-6y=15$

Next, combine like terms: $-12y+27=15$

Subtract 27 on each side: $-12y=-12$

Lastly, divide -12 on each side, and your answer should be $y=1$

To solve for x, just substitute y for 1 in either equation. For this Ill be doing the first equation.

$2(1)=-x+9$

Multiply 2 and 1 $2=-x+9$

Subtract 9 on each side $-7=-x$

Lastly, flip the signs, and your answer should be $7=x$

In short, the answer is (7,1).